풀리퀘스트를 병합하는 경우 Jira Automation 규칙
Posted by: Tara Kirkland
Generally, it’s best practice to put unique constraints on a table to prevent duplicate rows. However, you may find yourself working with a database where duplicate rows have been created through human error, a bug in your application, or uncleaned data from external sources. This tutorial will teach you how to find these duplicate rows.
To follow along, you’ll need read access to your database and a tool to query your database.
애자일 너머를 향해
The first step is to define your criteria for a duplicate row. Do you need a combination of two columns to be unique together, or are you simply searching for duplicates in a single column? In this example, we are searching for duplicates across two columns in our Users table: username and email.
애자일 너머를 향해
The first query we’re going to write is a simple query to verify whether duplicates do indeed exist in the table. For our example, my query looks like this:
SELECT username, email, COUNT(*)
FROM users
GROUP BY username, email
HAVING COUNT(*) > 1HAVING is important here because unlike WHERE, HAVING filters on aggregate functions.
If any rows are returned, that means we have duplicates. In this example, our results look like this:
USERNAME | | COUNT |
|---|---|---|
| Pete | pete@example.com | 2 |
| Jessica | jessica@example.com | 2 |
| Miles | miles@example.com | 2 |
애자일 너머를 향해
In the previous step, our query returned a list of duplicates. Now, we want to return the entire record for each duplicate row.
To accomplish this, we’ll need to select the entire table and join that to our duplicate rows. Our query looks like this:
SELECT a.*
FROM users a
JOIN (SELECT username, email, COUNT(*)
FROM users
GROUP BY username, email
HAVING count(*) > 1 ) b
ON a.username = b.username
AND a.email = b.email
ORDER BY a.emailIf you look closely, you’ll see that this query is not so complicated. The initial SELECT simply selects every column in the users table, and then inner joins it with the duplicated data table from our initial query. Because we’re joining the table to itself, it’s necessary to use aliases (here, we’re using a and b) to label the two versions.
Here is what our results look like for this query:
ID | USERNAME | |
|---|---|---|
| 1 | Pete | pete@example.com |
| 6 | Pete | pete@example.com |
| 12 | Jessica | jessica@example.com |
| 13 | Jessica | jessica@example.com |
| 2 | Miles | miles@example.com |
| 9 | Miles | miles@example.com |
Because this result set includes all of the row ids, we can use it to help us deduplicate the rows later.